Question

URGENT!

Hello, I am having trouble trying to figure out how I need to do this problem for my C++ class.

The assignment is asking me to write a program that will count the number of EVEN digits in a given number.

This is my first Programming class so please bare with me.

My current code is below:


int countEven (int n);

int even_count = 0;

int n;

while (n > 0)

{

int rem = n % 10;

if (rem % 2 == 0)

even_count++;

}

if (even_count % 2 == 0)

even_count++;

std::cout << "Even Digits Program\\";

std::cout << "Enter a number greater than 0.\\";

std::cin >> n;

std::cout << "This number has " << even_count << " even digit(s).";

The problem I am having is that it keeps returning 1 even digit for any number I input.

If you could help me with this I would greatly appreciate it.

Answer 1

Step-by-step explanation:

Hey there! you need not to panic about it ,your program didn't have Driver program i.e main program! the correct & working code is given below:

// C++ program to count even digits in a given number .

#include <iostream>

using namespace std;

// Function to count digits

int countEven(int n)

{

int even_count = 0;

while (n > 0)

{

int rem = n % 10;

if (rem % 2 == 0)

even_count++;

n = n / 10;

}

cout << "Even count : "

<< even_count;

if (even_count % 2 == 0 )

return 1;

else

return 0;

}

// Driver Code

int main()

{

int n;

std::cin >>n;

int t = countEven(n);

return 0;

}