Question

A gas has a volume of 490. mL at a temperature of -35.0 degrees C. What volume would the gas occupy at 42.0 degrees Celsius? Please show work.

Answer 1

648.5 mL

Step-by-step explanation:

Here we will assume that the pressure of the gas is constant, since it is not given or specified.

Therefore, we can use Charle's law, which states that:

"For an ideal gas kept at constant pressure, the volume of the gas is proportional to its absolute temperature"

Mathematically:

`(V)/(T)=const.`

where

V is the volume of the gas

T is its absolute temperature

The equation can be rewritten as

`(V_1)/(T_1)=(V_2)/(T_2)`

where in this problem we have:

`V_1=490 mL` is the initial volume of the gas

`T_1=-35.0^(\circ) + 273 = 238 K` is the initial temperature

`T_2=42.0^(\circ)+273=315 K` is the final temperature

Solving for V2, we find the final volume of the gas:

`V_2=(V_1 T_2)/(T_1)=((490)(315))/(238)=648.5 mL`