Question

James decides to walk from school to the park tp play ball. The park is only 0.5 mile from the school. He leaves school at 3:15 and arrives at the park at 3:25. At what rate is james traveling

Answer 1

Answer:
`0.05\ (mi)/(min)`

Explanation:

For this exercise you need to remember the following formula:

`V=(d)/(t)`

Where "V" is the speed, "d" is the distance and "t" is time.

In this case, according to the information given in the exercise, you know that:

- James leaves his school at 3:15 and arrives at the park at 3:25. Then, you can identify that the time it takes him to go from his school to the park is:

`t=10\ min`

- The park is 0.5 miles from James' school. Therefore, you can identify that "d" is:

`d=0.5\ mi`

So, knowing those values, you can substitute them into the formula:

`V=(0.5\ mi)/(10\ min)`

Finally, evaluating, you get the following result:

`V=0.05\ (mi)/(min)`