Question

In the interval 0 degrees Find the value for x in which sin=0.6691
To the nearest degree

Answer 1

42° and 138°.

Explanation:

Here we use the identity that

`sin (x) = sin(180-x )`.

Now, to find
`x`, we make use of the inverse sine function:

`x = sin^(-1)(0.0091)`

`\boxed{ x = 42^o.}`

Another solution to this is

`x_0= 180 -x= 180-42 \\\\\boxed{ x_0 = 138^o}`

Thus, the values of
`x` in the interval
`0<x<360` for which
`sin(x) =0.6691` are 42° and 138°.