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A car with a total mass of 1800 kg (including passengers) is driving down a washboard road with bumps spaced 4.2 m apart. The ride is roughest—that is, the car bounces up and down with the maximum amplitude—when the car is traveling at 8.0 m/s.

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Incomplete question.The complete is here

A car with a total mass of 1800 kg (including passengers) is driving down a washboard road with bumps spaced 4.2 m apart. The ride is roughest—that is, the car bounces up and down with the maximum amplitude—when the car is traveling at 8.0 m/s.What is the spring constant of the car's springs?

Answer:

Step-by-step explanation:

The frequency is calculated as:


f=(8.0m/s)/(4.2m)\\ f=1.905Hz

As we know that
k=257.6kN/m


f=(1)/(2\pi ) \sqrt{(k)/(m) }\\ k=m(2\pi f)^(2)\\ k=1800kg[2\pi (1.905Hz)]^(2) \\k=257.6kN/m

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