Answer:
17.85% is the organic content of the carrot tissue.
Step-by-step explanation:
Percentage of water is carrot sample = 79%
Mass of the sample = M
Mass of the water is sample = 79% of M = 0.79M
Percentage of dried carrot sample = 100%-79%=21%
Mass of the carrot sample after drying = 8 g
![21\%=(8 g)/(M)* 100](https://img.qammunity.org/2021/formulas/chemistry/college/3ijfsofyok3xzix97gtx0yzm6j6zrd9flr.png)
![M=38.10 g](https://img.qammunity.org/2021/formulas/chemistry/college/95xll93wzk9ou4sngh50jvj984oxq85jl3.png)
Mass of ash =- 1.2 g
Mass of organic matter = 8 g - 1.2 g = 6.8 g
Percentage of organic matter ;
![=(6.8 g)/(38.10 g)* 100=17.85\%](https://img.qammunity.org/2021/formulas/chemistry/college/v84ff60igkm9szqoy1z3d6sp3pbim5c1n8.png)
17.85% is the organic content of the carrot tissue.