Answer:
a) 0.1165
b) 0.0983
c) 0.000455
d) 0.787
e) 0.767
Explanation:
5 bars, 4 lemons, 3 cherries, and a bell
Total = 5+4+3+1 = 13
The probability of getting a bar on a slot, P(Ba) = 5/13 = 0.385
A lemon, P(L) = 4/13 = 0.308
A cherry, P(C) = 3/13 = 0.231
A bell, P(Be) = 1/13 = 0.0769
a) Probability of getting 3 lemons = (4/13) × (4/13) × (4/13) = 256/2197 = 0.1165
b) Probability of getting no fruit symbol
On each slot, there are 4+3 = 7 fruit symbols.
Probability of getting a fruit symbol On a slot = 7/13
Probability of not getting a fruit symbol = 1 - (7/13) = 6/13 = 0.462
Probability of not getting a fruit symbol On the three slots = 0.462 × 0.462 × 0.462 = 0.0983
c) Probability of getting 3 bells, the jackpot = (1/13) × (1/13) × (1/13) = 1/2197 = 0.000455
d) Probability of not getting a bell on the 3 slots
Probability of not getting a bell on one slot = 1 - (1/13) = 12/13 = 0.923
Probability of not getting a bell on the 3 slots = (12/13) × (12/13) × (12/13) = 1728/2197 = 0.787
e) Probability of at least one bar is a sum of probabilities
Note that Probability of getting a bar = 5/13 and probability of not getting a bar = 8/13
1) Probability of getting 1 bar and other stuff on the 2 other slots (this can happen in 3 different orders) = 3 × (5/13)×(8/13)×(8/13) = 960/2197 = 0.437
2) Probability of getting 2 bars and other stuff on the remaining slot (this can also occur in 3 different orders) = 3 × (5/13)×(5/13)×(8/13) = 600/2197 = 0.273
3) Probability of getting 3 bars on the slots machine = (5/13) × (5/13) × (5/13) = 125/2197 = 0.0569
Probability of at least one bar = 0.437 + 0.273 + 0.0569 = 0.7669 = 0.767