Answer:
The wavelength of this radiation is 0.06 m.
Step-by-step explanation:
Given that,
Frequency = 5000 MHz
We know that,
Speed of light
![c= 3*10^(8)\ m/s](https://img.qammunity.org/2021/formulas/physics/high-school/xxenbi54vmln7pzuid86yu5mptqixztm4h.png)
We need to calculate the wavelength of this radiation
Using formula of wavelength
![\lambda=(c)/(\\u)](https://img.qammunity.org/2021/formulas/physics/high-school/ak93asvgr8nikzc28hfh2n8ikaqky1qvso.png)
Where,
= wavelength
= frequency
c = speed of light
Put the value into the formula
![\lambda=(3*10^(8))/(5*10^(9))](https://img.qammunity.org/2021/formulas/physics/high-school/om3ir2squ629fa3zt1kbh4n5ikzpmdiwb9.png)
![\lambda=0.06\ m](https://img.qammunity.org/2021/formulas/physics/high-school/oquegmy1l3py013jt30zzti5gq8yykhppj.png)
Hence, The wavelength of this radiation is 0.06 m.