Question

OMG I'M HAVING A BRAIN FART AND CAN"T SOLVE THIS FOR THE LIFE OF ME. HELPPPP!

Answer 1

side=Perimeter/4

side:-

`\\ \rm\Rrightarrow (4(x^2+1))/(4(x^2-2x+19)`

`\\ \rm\Rrightarrow (x^2+1)/(x^2-2x+19))✓/tex]</p><p></p><p>Area=side ²</p><p></p><p>[tex]\\ \rm\Rrightarrow \left((x^2+1)/(x^2-2x+19)\right)^2`

Answer 2

Explanation:

Because a square has 4 equal sides:

P = 4x

A =
`x^(2)`

Step 1. Substitute 4x into perimeter equation

`P=(4x^2+4)/(x^2-2x+1)` (original P equation)

`4x=(4x^2+4)/(x^2-2x+1)` (substitute P = 4x)

Step 2. Solve for x

`4x(x^2-2x+1)={4x^2+4}` (multiply denominator on both sides)

`4x^3-8x^2+4x={4x^2+4}` (distribute 4x)

`4x^3-12x^2+4x-4=0` (combine like terms, set = to 0)

`4(x^3-3x^2+x-1)=0` (factor)

Continue using quadratic formula to find x

Step 3. Plug x into area equation,
`x^(2)`

Hope this helps! Cannot finish answer right now, so sorry