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A polymer bar’s dimensions are 1 in. 3 2 in. 3 15 in. The polymer has a modulus of elasticity of 600,000 psi. What force is required to stretch the bar elastically from 15 in. to 15.25 in.?
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A polymer bar’s dimensions are 1 in. 3 2 in. 3 15 in. The polymer has a modulus of elasticity of 600,000 psi. What force is required to stretch the bar elastically from 15 in. to 15.25 in.?

User Odupont
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1 Answer

3 votes

Answer: Force= 297,000 N

Step-by-step explanation:

Strain, stress and Hooke's Law will be used to solve this problem.

(The attachment below shows the calculations)

A polymer bar’s dimensions are 1 in. 3 2 in. 3 15 in. The polymer has a modulus of-example-1
User Antonyboom
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