Answer:
![5.2* 10^5N/C](https://img.qammunity.org/2021/formulas/physics/high-school/zpv1z9kqvrjvx2pp7o5v37qmpajsdj1sah.png)
Step-by-step explanation:
Since the two charged bodies are symmetric, we can calculate the electric field taking both of them as point charges.
This can be easily seen if we use Gauss's law,
![\int{E} \, dA=(Q_(enclosed))/(\epsilon_o)](https://img.qammunity.org/2021/formulas/physics/high-school/rnje8qmdgikgwlr280fl9nrktd4722kz8r.png)
We take a larger sphere of radius, say r, as the Gaussian surface. Then the electric field due to the charged sphere at a distance r from it's center is given by,
![E=(1)/(4\pi r^2) (Q_(enclosed))/(\epsilon_o)](https://img.qammunity.org/2021/formulas/physics/high-school/yu6a0o8rgu81t57343iushcwqkk5mp919j.png)
which is the same as that of a point charge.
In our problem the charges being of opposite signs, the electric field will add up. Therefore,
![E_(total)=(1)/(4\pi\epsilon_o)(q_1+q_2)/(r^2)= (9*10^9) ((76+30)*10^(-9))/(((1+3.3)*10^(-2))^2)N/C =5.2*10^5N/C](https://img.qammunity.org/2021/formulas/physics/high-school/ev9zdxb3upo3i0x9gzgvytmxgrxxb9k981.png)
where,
= distance between the center of one sphere to the midpoint (between the 2 spheres)