Question

Give the first five terms of the sequence
an=2n2+2

Answer 1

The answer to your question is 3, 9, 19, 33, 51

Explanation:

Sequence an = 2n² + 1

1st term a₁ = 2(1)² + 1 = 2(1) + 1 = 2 + 1 = 3

2nd term a₂ = 2(2)² + 1 = 2(2)² + 1 = 2(4) + 1 = 8 + 1 = 9

3rd term a₃ = 2(3)² + 1 = 2(3)² + 1 = 2(9) + 1 = 18 + 1 = 19

4rd term a₄ = 2(4)² + 1 = 2(4)² + 1 = 2(16) + 1 = 32 + 1 = 33

5th term a₅ = 2(5)² + 1 = 2(5)² + 1 = 2(25) + 1 = 50 + 1 = 51