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X squared + 14 x + 17 = negative 96

1 Answer

4 votes


\text{Hey there!}


\mathsf{The\ quadratic\ formula\ is: ax^2+bx+c=0}


\mathsf{Use\ this\ formula\ to\ solve: x=(-b\pm√(b^2-4ac))/(2a)}


\mathsf{ax^2=x^2}


\mathsf{bx=14x}


\mathsf{c=17}


\mathsf{0=96}


\mathsf{x^2+14x+17=96}


\text{Subtract by 96 on your sides}


\mathsf{x^2+14x+17-96=96-96}


\text{Cancel out: 96 - 96 because it gives you the result of 0}


\text{Keep: 17 - 96 because it helps us solve for our equation. 17 - 96 = -79}


\mathsf{x^2+14x-79=0}


\mathsf{Use\ the\ 2^(nd)\ formula\ to\ solve}


\mathsf{x=(-14)\pm((14)^2-4(1)(-79))/(2)(1))}


\mathsf{(14)^2-4(1)(-79)=196-4(1)(-79)\rightarrow512}


\mathsf{2(1)=2}


\mathsf{x=(-14\pm√(512))/(2)}


\mathsf{Solve\ that\ above\ and\ you\ have\ your\ result!}


\boxed{\mathsf{Thus\ your\ answer\ is: x=-7+8√(2)\ or\ x = -7-8√(2)}}\checkmark


\text{Good luck on your assignment and enjoy your day!}

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