Answer:
1
Step-by-step explanation:
From the question, the following were obtained:
Mass of hydrated salt(Na2CO3.XH2O) = 4.133g
Mass of anhydrous salt(Na2CO3) = 3.533g
Mass of water = 4.133 — 3.533 = 0.6g
Next, we convert these grams to moles
MM of Na2CO3 = (23 x 2)+12+(16x3) = 46+12+48) = 106g/mol
Number of mole = Mass /Molar Mass
Number of mole of Na2CO3 = 3.533/106 = 0.033mol
MM of water (H2O) = (2x1) +16 = 2+16 =18g/mol
Number of mole of H2O = 0.6/18 = 0.033mol
Next, we find the ratio of the mole of anhydrous salt to the water. This done below:
Mole of anhydrous : mole of water = 0.033 : 0.033 = 1 : 1
The number of mole of water attached to the salt is 1
The formula of the hydrated salt is CuSO4.H2O