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A Semi truck(m=20,000kg) is 10 m from a car(m=200kg). What is the force of gravity between them(G=6.67*10^-11N•m^2/kg^2)

2 Answers

7 votes

Answer:

2.67 x 10^-5 N

User Sjay
by
4.3k points
5 votes

Answer:

F = 2.668*10_-6[N]

Step-by-step explanation:

We can calculate this force using the law of universal gravitation raised by Isaac Newton


m_(t)=20000[kg]\\m_(c)= 200[kg]\\r = 10[m]\\G = 6.67*10^(-11)[(N*m^(2) )/(kg) ] \\

And the force is given by the following expression:


F=G*(m_(t)*m_(c))/(r^(2) ) \\F=6.67*10^(-11) *(20000*200)/(10^(2) )\\F=2.668*10^(-6) [N]

User Naga Vijayapuram
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4.0k points