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If tan0 = 12/5 and cos0 = -5/13, then what is sin0

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Question:

if tan
\theta = 12/5 and cos
\theta = -5/13, then what is sin
\theta

Answer:


sin \theta = ( -12)/(13)

Explanation:

Given:

tan
\theta = 12/5

cos
\theta = -5/13

To find:

sin
\theta = ?

Solution:

We can find the sin
\theta value by using the tan ratio and cosine ratio


cos = ( adjacent )/(hypotenuse) = ( -5)/(13)


sin = ( opposite)/(hypotenuse)


sin \theta = tan \theta * cos\theta


sin \theta = (opposite)/(adjacent) * (adjacent)/(hypotenuse) =
( opposite)/(hypotenuse)

On substituting the values,


sin \theta = ( 12)/(5) * (-5)/(13)


sin \theta = ( -12)/(13)

User Aaron Ray
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