Option A: z + 1
Option B: 6 + w
Option D:
![2 x^(4)-y](https://img.qammunity.org/2021/formulas/mathematics/middle-school/6y9ls43k1arwcwzsfdsgffvll893e11svf.png)
Solution:
Let us first define the polynomial.
A polynomial can have constants, variables, exponents and fractional coefficients.
A polynomial cannot have negative exponents, fractional exponents and never divided by a variable.
To find which expressions are polynomial:
Option A: z + 1
By the definition, z + 1 is a polynomial.
It is polynomial.
Option B: 6 + w
By the definition, 6 + w is a polynomial.
It is polynomial.
Option C:
![y^(2)-\sqrt[3]{y}+4](https://img.qammunity.org/2021/formulas/mathematics/middle-school/vrjg2rafmz61fgjmrhz38bl6fahnivrq4z.png)
![y^(2)-\sqrt[3]{y}+4=y^(2)-{y}^(1/3)+4](https://img.qammunity.org/2021/formulas/mathematics/middle-school/cvieg11ftz3yg1xnffpsp7m6flgzreqjmd.png)
Here, y have fractional exponent.
So, it is not a polynomial.
Option D:
![2 x^(4)-y](https://img.qammunity.org/2021/formulas/mathematics/middle-school/6y9ls43k1arwcwzsfdsgffvll893e11svf.png)
By the definition,
is a polynomial.
It is polynomial.
Hence z + 1, 6 +w and
are polynomials.