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E=IZ
Where E=(5+9i) and I=(8+7i)
How do I solve for Z?

User Pull
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1 Answer

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Answer:


Z = (37i )/(113 ) - (23)/(113)

Explanation:

We have the complex number relationship as:

E=IZ

Where E=(5+9i) and I=(8+7i)

We solve for Z to get;

Z=E/L

We then substitute the expressions to get:


Z = (5 + 9i)/(8 + 7i)

We rationalize to get:


Z = (5 + 9i)/(8 + 7i) * (8 - 7i)/(8 - 7i)

We simplify to obtain:


Z = \frac{40 - 35i + 72i - 63}{ {8}^(2) + {7}^(2) }

This gives


Z = (37i - 23)/(113 )

Or


Z = (37i )/(113 ) - (23)/(113)

User Bytesized
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