Question

Saturated steam coming off the turbine of a steam power plant at 40oC condenses on the outside of a 7.421-cm-outer-diameter, 2.916-m-long tube at a rate of 16.154 kg/h. Calculate the rate of heat transfer in kW (give your answer with 3 decimals, do NOT enter units!!!).

Answer 1

Rate of heat transfer will be 10.69 kw

Step-by-step explanation:

We have given temperature
`T=40^(\circ)C`

From standard table enthalpy of vaporization 2382.75 KJ/kg

Steam is coming out from turbine at rate of 16.154 kg/hour

We have to calculate the rate of heat transfer

Heat transfer is equal to
`Q=mass* enthalpy\ of \ vaporization`

So rate of heat transfer
`=16.154* 2382.75=38490.94KJ/hr`

=
`=16.154* 2382.75=38490.94* (1)/(3600)watt=10.691kwatt`

So rate of heat transfer will be 10.69 kw