Question

Find the number of grams of HCl needed to react completely with .50 moles of magnesium. Mg(s) + 2HCl(aq) --> MgCl2(aq) + H2(g)

Answer 1

36.46 g of HCl

Step-by-step explanation:

The balance chemical equation for given single replacement reaction is as follow;

Mg + 2 HCl → MgC₂ + H₂

Step 1: Calculate Moles of HCl required:

According to equation,

1 mole of Mg reacted with = 2 moles of HCl

So,

0.5 moles of Mg will react with = X moles of HCl

Solving for X,

X = 0.5 mol × 2 mol / 1 mol

X = 1 mol of HCl

Step 2: Calculate Mass of HCl as;

Moles = Mass / M.Mass

Or,

Mass = Moles × M.Mass

Mass = 1 mol × 36.46 g/mol

Mass = 36.46 g of HCl