Question

Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3 ( is ) . The equation for the reaction is 2 KClO3 ⟶ 2 KCl + 3 O 2 Calculate how many grams of O 2 ( g ) can be produced from heating 66.8 g KClO 3 ( s ) .

Answer 1

The answer to your question is 52.35 g of O₂

Step-by-step explanation:

mass of oxygen = ?

mass of KClO₃ = 66.8 g

Chemical balanced reaction

KClO₃ ⇒ 2 KCl + 3O₂

Process

1.- Calculate the molar mass of KClO₃ and Oxygen

KClO₃ = 39 + 35.5 + (16 x 3) = 122.5 g

O₂ = 16 x 6 = 96 g

2.- Write proportions to solve this problem

122.5 g of KClO₃ ----------------- 96 g of O₂

66.8 g ----------------- x

x = (66.8 x 96) / 122.5

x = 6412.8/122.5

x = 52.35 g of O₂