Question

Find the solution to the equation:
f(x)=x^2-4x+3
Please show work!

Answer 1

Let's see

`\\ \rm\rightarrowtail f(x)=0`

`\\ \rm\rightarrowtail x^2-4x+3=0`

`\\ \rm\rightarrowtail x^2-3x-x+3=0`

`\\ \rm\rightarrowtail x(x-3)-1(x-3)=0`

`\\ \rm\rightarrowtail (x-1)(x-3)=0`

`\\ \rm\rightarrowtail x=1,3`

Answer 2

• two solutions

x = 1, 3

Step-by-step explanation:

`\sf f(x)=x^2-4x+3`

`\rightarrow \sf x^2-4x+3=0`

`\rightarrow \sf x^2-3x-x+3=0`

`\rightarrow \sf x(x-3)-1(x-3)=0`

`\rightarrow \sf (x-1)(x-3)=0`

`\rightarrow \sf x-1=0, \ x-3=0`

`\rightarrow \sf x=1, \ x=3`

Thus, there are two solutions and the values are 1 and 3