Question

Find dy/dx

y = 5/8x^3/7 + 8x^4 + 6x - 9

Answer 1

15/56x^(-4/7) + 32x^3 + 6.

Explanation:

Using the rule for algebraic differentiation:

If y = ax^n, dy/dx = anx^(n-1).

So :

If y = 5/8x^3/7 + 8x^4 + 6x - 9

dy/dx = 5/8* 3/7 x^(3/7-1) + 8*4 x^(4-1) + 6x(1-1)

= 15/56x^(-4/7) + 32x^3 + 6.