Question

Find all of the zeros of the function and write the polynomial as the product of linear factors.

h(x)=x^3+x^2+36x+36

Answer 1

(x+6i)(x-6i)(x+1)

So the zeroes are 6i, -6i, -1

Explanation:

Factor by grouping

h(x) = x^2(x+1) + 36(x+1)

h(x) = (x^2+36)(x+1)