Answer:
2.125 m/s
Step-by-step explanation:
From the law of conservation of momentum,
Total momentum before collision = Total momentum after collision.
Note: Assuming a inelastic collision occur between the grocery cart and the bag.
mv+m'v' = V(m+m')..................... Equation 1
Where m = mass of the cart, m' = mass of the bag, v = initial velocity of the grocery cart, v' = final velocity of the bag, V = Final velocity of the bag and the cart.
Making V the subject of the equation,
V = (mv+m'v')/(m+m')................. Equation 2
Given: m = 18.2 kg, m' = 8.1 kg, v' = 6.9 m/s, v = 0 m/s (stationary)
Substitute into equation 2
V = [(18.2×0)+(8.1×6.9)]/(8.1+18.2)
V = 55.89/26.3
V = 2.125 m/s.
Hence the final speed of the cart and the bag = 2.125 m/s