Answer:
112 – a fraction less than 12
Explanation:
We need to look for only one value that will invalidate the claim.
We denote the unknown in the condition with
.
Let's consider each individually:
1. 89 × a number less than 1
![89* x\le 1](https://img.qammunity.org/2021/formulas/mathematics/high-school/j33p3vway7vwl78mv6cdk3ya1915tldr8h.png)
![x\le (1)/(89)](https://img.qammunity.org/2021/formulas/mathematics/high-school/q45hzwvtk0mg5zlylvkenwlaybn0qtngqw.png)
We only need values that satisfy this inequality to invalidate the claim. Like 0, -1,...
2. 112 - a fraction less than 12
![112-x\le1](https://img.qammunity.org/2021/formulas/mathematics/high-school/4tf1kr3d5bs87aacvriuy55c9458b4u11c.png)
![112-1\le x](https://img.qammunity.org/2021/formulas/mathematics/high-school/td6enmm8pp0952hzvp7ugsvpl1iw6mbnqs.png)
![111\le x](https://img.qammunity.org/2021/formulas/mathematics/high-school/45fas9xkea1n3123mjo41apqhuzd9ms7b7.png)
![x\ge111](https://img.qammunity.org/2021/formulas/mathematics/high-school/8gd0zd1f96t4fn889iarijbfy4mamj3un2.png)
But this is a contradiction because
must be less than 12.
Hence, this is always true.
3. 25 + a fraction less than 12
![25+x\le1](https://img.qammunity.org/2021/formulas/mathematics/high-school/c4q5sb05ajva6rfpxxki3q0z4d9pn8s1d6.png)
![x\le1-25](https://img.qammunity.org/2021/formulas/mathematics/high-school/5vvlmikmmja98k9nn6r3f539560qucjdl5.png)
![x\le-24](https://img.qammunity.org/2021/formulas/mathematics/high-school/tyoqogodb3z4mvzpn0r6fqkqlmfd29y46z.png)
Hence, all fractions less than or equal to
will invalidate the claim. Like -24, -25,...
4. 10 × a number less than 1
![10* x\le 1](https://img.qammunity.org/2021/formulas/mathematics/high-school/3r0w49vpkeix1luj79c7wfse1tdfi0ppbn.png)
![x \le(1)/(10)](https://img.qammunity.org/2021/formulas/mathematics/high-school/i2qt3tyijd7skl18bz2y0ncfmjzdii82kl.png)
We only need values that satisfy this inequality to invalidate the claim. Like 0, -1,...