Question

Recall that the value of Kw for the autoionization of water varies with temperature. At the temperature of your body (37°C), Kw = 3.98 x 10-14 rather than 1.00 x 10-14. What is the pH of pure water at 37°C?

Answer 1

pH =6.70

Step-by-step explanation:

When Kw = 1x10^-14

[H3O+] = [OH-] --> 1x10-7

Kw =3.98x^10-14

3.98x^10-14 = [H3O+] . [OH-]

√ (3.98x^10-14) = [H3O+] = [OH-]

[H3O+] = 1.99×10^-7

- log [H3O+] = pH ---> -log 1.99x10^-7 = 6.70