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Suppose u and v are functions of x that are differentiable at x=0 and that u(0)=5, u'(0)=-5, v(0)=8, and v'(0)=-2.find the values of the following derivatives at x=0

a)d/dx(uv)=?

b)d/dx(u/v)=?

c)d/dx(v/u)=?

d)d/dx(-6v-9u)=?

User Kwelch
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1 Answer

3 votes

Answer:

a)-50

b)-15/32

c) 6/5

d) 57

Step-by-step explanation:

a)


(d)/(dx)(uv)


u(x)v'(x)+u'(x)v(x)

Evaluate this at
x=0 we get:


u(0)v'(0)+u'(0)v(0)


5(-2)+-5(8)


-10+-40


-50

b)


(d)/(dx)((u)/(v))


(u'(x)v(x)-u(x)v'(x))/((v(x))^2)

Evaluate this at
x=0 we get:


(u'(0)v(0)-u(0)v'(0))/((v(0))^2)


(-5(8)-5(-2))/((8)^2)


\frac[-40+10}{64}


(-30)/(64)


(-15)/(32)

c)


(d)/(dx)((v)/(u))


(v'(x)u(x)-v(x)u'(x))/((u(x))^2)

Evaluate this at
x=0 we get:


(v'(0)u(0)-v(0)u'(0))/((u(0))^2)


(-2(5)-8(-5))/((5)^2)


(-10+40)/(25)


(30)/(25)


(6)/(5)

d)


(d)/(dx)(-6v-9u)


-6v'(x)-9u'(x)

Evaluate this at
x=0:


-6v'(0)-9u'(0)


-6(-2)-9(-5)


12+45


57

User Tyler Jennings
by
7.1k points