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11 votes
11 votes
PLSSS HEELPPP A line passes through (3, -2) and (6, 2).

a. Write an equation for the line in point-slope form.
b. Rewrite the equation in standard form using integers.

a. y+2= 4/3(x+3); -4x+ 3y= -18
b. y+2= 4/3(x-3); -4x+3y= -18
c. y-2= 4/3(x-3); -4x+3y= 18
d. y-3= 4/3(x+2); -4x+3y= 17

User Orelsanpls
by
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1 Answer

15 votes
15 votes

Answer:

b)

Explanation:

Question (a)


\sf let \ (x_1,y_1)=(3,-2)\\\\\sf let \ (x_2,y_2)=(6,2)


\sf slope \ (m)=(y_2-y_1)/(x_2-x_1)=(2-(-2))/(6-3)=\frac43

Point-slope formula:
\sf y-y_1=m(x-x_1)

Substituting m and point (3, -2) into the formula:


\sf y-(-2)=\frac43(x-3)


\sf y+2=\frac43(x-3)

Question (b)

Rewrite in standard form:


\sf y+2=\frac43x-4


\sf \implies y=\frac43x-6


\sf \implies 3y=4x-18


\sf \implies -4x+3y=-18

User Itsazzad
by
2.8k points
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