Question

How do you solve this

Answer 1

x=-2

Explanation:

`\frac{1}{6{x}^(2) } = (1)/(2x) + \frac{7}{6 {x}^(2) } \\ \frac{7}{6 {x}^(2) } - \frac{1}{6{x}^(2) } + \frac{1}{2 {x} } = 0 \: \: \: \: \: ( - \frac{1}{6 {x}^(2) } \: throughout) \\ \frac{6}{6 {x}^(2) } + (1)/(2x) = 0 \: \: \: \: \: (simplify)\\ \frac{1}{ {x}^(2) } + (1)/(2x) = 0 \\ \frac{2 {x}^(2) }{ {x}^(2) } + \frac{2 {x}^(2) }{2x} = 0 \: \: \: \: \: ( * 2 {x}^(2) \: throughout) \\ 2 + x = 0 \: \: \: \: \: (simplify)\\ x = - 2`