Answer:
The correct answer is
e. NH3(aq) + H+(aq) --> NH4+(aq)
Step-by-step explanation:
To solve this, we write out the indidual ionization reation for aqueous ammonia and nitric acid thus
For aqueous ammonia we have
NH₃(aq) + H₂O(l) ↔ NH₄⁺(aq) + OH⁻(aq)
Aqueous ammonia is a weak base and therefore undergoes partial ionization hence the reversible reaction sign
As the level of ionization will not be more than 5% OH⁻ cannot represebt the weak base
For nitric acid we have
HNO₃(aq) → H⁺(aq) + NO₃⁻(aq)
a strong acid like nitric acid undergoes conplete ionization in the solution
The total equation is NH₃(aq) + HNO₃(aq) → NH₄NO₃(aq)
The sum of the ionic equation is
NH₃(aq) + H⁺(aq) + NO₃⁻(aq) → NH₄⁺(aq) + NO₃⁻(aq)
The ionic equation is
NH₃(aq) + H⁺(aq) → NH₄⁺(aq)