Question

A tetrahedron has an equilateral triangle base with 25.0-cm-long edges and three equilateral triangle sides. The base is parallel to the ground, and a vertical uniform electric field of strength 260N/C passes upward through the tetrahedron.

What is the electric flux through the base?







What is the electric flux through each of the three sides?

Answer 1

-7.03645640575 Nm²/C

2.34548546858 Nm²/C

Step-by-step explanation:

S = Surface area

Electric flux through the base is given by

`\phi_b=-\int Eds\\\Rightarrow \phi_b=-ES\\\Rightarrow \phi_b=-260(√(3))/(4)0.25^2\\\Rightarrow \phi_b=-7.03645640575\ Nm^2/C`

The electric flux through the base is -7.03645640575 Nm²/C

Inside the tetrahedron there is no charge so total flux will be zero

`\phi_b+3\phi_s=0\\\Rightarrow \phi_s=-(\phi_b)/(3)\\\Rightarrow \phi_s=-(-7.03645640575)/(3)\\\Rightarrow \phi_s=2.34548546858\ Nm^2/C`

The electric flux through the sides is 2.34548546858 Nm²/C