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Alex threw a ball into a basketball hoop. The height of the ball, in feet, is represented by the function h(t)=-8(t-2)^2+13, where t is time in seconds. From what height did Alex throw the ball?

Please show all work and any incorrect or incomplete answers will be reported.

User Mhradek
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1 Answer

2 votes

Answer:

The answer to your question is Alex threw the ball from 45.

Explanation:

function h(t) = 8(t - 2)² + 13

time = t = [seconds]

If we need to know the height from which Alex threw the ball, we need to consider that the time was zero, nothing has happened yet.

Evaluate the function when t = 0

h(0) = 8(0 - 2)² + 13

Simplification

h(0) = 8(-2)² + 13

h(0) = 8(4) + 13

h(0) = 32 + 13

h(0) = 45

User SavageWays
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