Answer:
Molarity for the sulfuric acid is 0.622 M
Step-by-step explanation:
When we neutralize an acid with a base, molarity of both . both volume are the same. The formula is:
M acid . volume of acid = M base . volume of base
M acid = unknown
Volume of acid = 17 mL
Volume of base = 45 mL
M base = 0.235 M
Therefore, we replace: M acid . 17 mL = 0.235 M . 45 mL
M acid = (0.235 M . 45 mL) / 17 mL
M acid = 0.622 M