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A defibrillator passes 14.0 A of current through the torso of a person for 0.0300 s. How much charge moves in coulombs?

User Cschneid
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1 Answer

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The electric intensity concept defines that this is equivalent to the amount of load transported during a certain time. Under this same relationship it is possible to clear and obtain the load, which would be given as,


\Delta Q = I\Delta t

Here,

I = Current passing


\Delta t = Time taken to pass current

Replacing with our values we have that,


\Delta Q = (14)(0.03)


\Delta Q = 0.42C

Therefore the total charge move will be 0.42C

User Pierrebo
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