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The force between two objects, each of charge +Q is measured as +F when the objects are separated a distance d apart. If the charge on each object is doubled, determine the new force between them:

User Djbp
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2 Answers

3 votes

Answer:

4F

Step-by-step explanation:

User Jerry Dodge
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4 votes

Answer:


F'=4F

Step-by-step explanation:

According to Coulomb's law, the magnitude of the force (F) between two objects with the same charge(+Q), separated a distance (d) apart, is defined as:


F=(kQ^2)/(d^2)

Here k is the Coulomb constant. The charge on each object is doubled, that is
Q'=2Q:


F'=(kQ'^2)/(d^2)\\F'=(k(2Q)^2)/(d^2)\\F'=4(kQ^2)/(d^2)\\F'=4F

User Ruediger Jungbeck
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