Question

A mole of gas at 0.0oC and 760. torr occupies 22.4 L. What is the volume of this gas at 25.oC and 760. torr

Answer 1

Step-by-step explanation:

Given

Temperature of gas at First stage
`T_1=0^(\circ)C\approx 273\ K`

Pressure of gas at First stage
`P_1=760\ torr`

Volume Occupies
`V_1=22.4\ L`

If the Pressure and Temperature at second stage is

`P_2=760\ torr`

`T_2=25^(\circ)C\approx 298\ K`

Using ideal gas Equation

`PV=nRT`

where P=Pressure

V=volume

R=Universal Gas constant

T=Temperature

n=no of moles

as n and R is constant therefore

`(PV)/(T)=constant`

thus
`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

`V_2=(760)/(760)* (298)/(273)* 22.4`

`V_2=24.45\ L`