Question

the digits of a two digit number sum to 8. When the digits are reserved, the resulting number is 18 less than the original number. What is the original number

Answer 1

53

Explanation:

The difference that results from reversing the digits (18) is 9 times the difference of the digits.

• The two digits sum to 8.
• The two digits differ by 2.

If we let "t" represent the tens digit, then we have ...

t +(t-2) = 8

2t = 10 . . . . . add 2

t = 5 . . . . . . . divide by 2

Then the ones digit is 5-2 = 3, and the original number is 53.

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Check

53 -35 = 18