Answer:
62.93%
Explanation:
We know that mean=9.4 lb and standard deviation=4.2 lb.
We have to find P(x≥8).
P(x≥8)=P((x-mean)/sd≥(8-9.4)/4.2)
P(x≥8)=P(z≥(-0.3333)
Rounding z score to 0.33
P(x≥8)=P(-0.33<z<0)+P(0<z<∞)
Using normal area table and we get P(-0.33<z<0)=0.1293
P(x≥8)=0.1293+0.5
P(x≥8)=0.6293
The percentage of households throw out at least 8 lb of paper a week is 62.93%