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If Two stars, Betty and Wilma, are both on the main sequence. Betty is more luminous than Wilma. Which one has a hotter surface temperature? Which one is more massive? Which one is bigger? If they both formed at the same time, which one will evolve off the main sequence first?

User Trilby
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1 Answer

4 votes

Answer:

Betty

Step-by-step explanation:

Since they're both on the most sequence but Betty is more luminous than Wilma, Betty must be located to a higher place on the most sequence. Therefore, Betty encompasses a hotter surface temperature, is more massive, and encompasses a larger radius. Betty also will evolve faster than Wilma, and if they were formed at the identical time Betty will put off the most sequence first

User Jack Gajanan
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