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Write the equation of the circle with center (0,0) and (3,6) a point on the circle

User Physicsboy
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1 Answer

3 votes

Answer:

( 3^2 + 4^2) B

Explanation:

The general equation of a circle is (x - a)^2 + (y - b)^2 = r^2, where the center is at (a , b) and the radius is r.

Now we have the center of the circle at (0,0). It passes through the point (3,4).

So the radius is sqrt ( 3^2 + 4^2)

=> sqrt ( 16 + 9)

=> sqrt 25

=> 5

Substituting the coordinates of the center (0,0) and the radius 5, we get (x - 0)^2 + (y - 0)^2 = 5^2

=> x^2 + y^2 = 25

The equation of the circle is x^2 + y^2 = 25

User Crag
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