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41 votes
41 votes
What is the solution of the inequality 9 - x^2<0?

User Tamarabyte
by
3.0k points

1 Answer

9 votes
9 votes

Answer:


x < -3\quad \mathrm{or}\quad \:x > 3

Explanation:

Given:


9-x^2 < \:0

Solve:


\mathrm{Subtract\:}9\mathrm{\:from\:both\:sides}


9-x^2-9 < 0-9


\mathrm{Simplify}


-x^2 < -9


Multiply\:both\:sides\:by\:-1\:


\left(-x^2\right)\left(-1\right) > \left(-9\right)\left(-1\right)


\mathrm{Simplify}


x^2 > 9


\mathrm{For\:}u^n\: > \:a\mathrm{,\:if\:}n\:\mathrm{is\:even}\mathrm{\:then\:}u\: < \:-\sqrt[n]{a}\:or\:u\: > \:\sqrt[n]{a}


x < -√(9)\quad \mathrm{or}\quad \:x > √(9)


√(9)=3


x < -3\quad \mathrm{or}\quad \:x > 3

~lenvy~

User Joelmob
by
3.0k points
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