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A body of mass 5kg is ejected vertically from the ground when a force of 600N acts on it for 0.1s.Calculate the velocity with which the body leaves the ground.​

User Vadym Vasyliev
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1 Answer

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Final answer:

The velocity with which a 5kg body leaves the ground after a 600N force acts on it for 0.1s is 12 meters per second, calculated using the impulse-momentum theorem.

Step-by-step explanation:

The question asks to calculate the velocity with which a 5kg body leaves the ground after a force of 600N acts on it for 0.1s. To determine this, one can use the impulse-momentum theorem which states that the impulse applied to an object is equal to the change in momentum of the object. The impulse is the product of the force and the time for which it acts (Impulse = Force x Time).

The momentum of the body is the product of its mass and velocity (Momentum = Mass x Velocity). Assuming the body starts from rest, the change in momentum is equal to its final momentum, since its initial momentum was zero.

The calculation involves multiplying the force (600N) by the time (0.1s) to find the impulse, and then dividing that by the body's mass (5kg) to find the velocity.

Impulse = 600N x 0.1s = 60NsVelocity = Impulse / Mass = 60Ns / 5kg = 12m/s

Therefore, the body leaves the ground with a velocity of 12 meters per second.

User Jefelewis
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