Answer:
- Rounding to nearest tenth of centimeter, the ball bounces 192.1 cm high on the 5th bounce.
Step-by-step explanation:
The ball is dropped from a height of 900 centimeters.
Since the heights form a geometric sequence, you can find a common ratio between consecutive terms. This is:
- Height bounce 2 / height bounce 1 = 560 / 800 = 0.7
- Height bound 3 / height bounce 2 = 392 / 560 = 0.7
Hence, the ratio of the geometric sequence is 0.7, and taking bounce 1 as the start of the sequence, the general term of the sequence is:
![a_n=800(0.7)^(n-1)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/3xi724s40jfzppjb43cljqlpl0jqua87nl.png)
With that formula you can find any term:
![n=1,a_1=800(0.7)^((1-1))=800(0.7)^0=800\\ \\ n=2,a_(2)=800(0.7)^((2-1))=800(0.7)=560\\ \\n=5,a_(5)=800(0.7)^((5-1))=800(0.4)^4=192.08](https://img.qammunity.org/2021/formulas/mathematics/middle-school/dmxxgca7chdw5wtphill6w6w7rdfot59x1.png)
Rounding to nearest tenth of centimeter, the ball bounces 192.1 cm high on the 5th bounce.