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What is the value of c so that -12 and 12 are both solutions of x^2-c=108? ​
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What is the value of c so that -12 and 12 are both solutions of x^2-c=108? ​

User Anvay
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1 Answer

3 votes

Answer:

c=36

Explanation:

  1. Because
    x^2-c=108 can be rewritten as
    x^2-c-108=0, finding the value of c so that x=(+-)12 solves this equation it means to find the value of c so that
    (+-)12^2-c-108=0.
  2. Because
    12^2=(-12)^2=144, we must find c so that
    144-c-108=0.
  3. Because
    144-108=36, c=36.
  4. To check, replace c=36 in the initial equation, and check it is a solution for x=(+-)12.
User Hasan Khan
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