Question

A particle moves in a straight line with an initial velocity of 35 m/s and a constant acceleration of 38 m/s2. If at t = 0, x = 0, what is the particle's position (in m) at t = 6 s?

Answer 1

d=894 m

Step-by-step explanation:

Given that

initial velocity ,u= 35 m/s

Acceleration ,a= 38 m/s²

time ,t= 6 s

Given that at t= 0 s ,x= 0 m

We know that

`d=ut+(1)/(2)at^2`

d=Displacement

Now by putting the values

`d=35* 6+(1)/(2)* 38* 6^2`

d=894 m

Therefore the particle position after 6 sec will be 894 m.