The solution to system is x = 0 and y = -1
Solution:
Given system of equations are:
-8x + 2y = -2 ----------- eqn 1
4x + 4y = -4 ---------- eqn 2
We have to solve the system of equations
We can solve the equations by elimination method
Multiply eqn 2 by 2
8x + 8y = -8 ------ eqn 3
Add eqn 1 and eqn 3
-8x + 2y = -2
8x + 8y = -8
( + ) ---------------
0x + 2y + 8y = -2 - 8
10y = -10
Divide both sides by 10
y = -1
Substitute y = -1 in eqn 1
-8x + 2(-1) = -2
-8x - 2 = -2
-8x = -2 + 2
x = 0
Thus the solution to system is x = 0 and y = -1