Question

Harry solves the equation 1/3t=15. He says the solution is 30. Is his solution correct.

Harry can first substitute (blank) for t. He can the multiply 1/3 by (blank) to get a product of (blank). Since 15 (blank) equal to (blank), Harry's solution (blank) correct

Answer 1

Harry's solution is incorrect.

Harry can first substitute (30) for t. He can the multiply 1/3 by (30) to get a product of (10). Since 15 (≠) equal to (10), Harry's solution is (not) correct.

Explanation:

Given:

Equation =
`(1)/(3)(t) =15`

Solution of the equation =
`30`

Lets check the equation whether both sides of the equation gives same result by plugging the values of t = 30.

⇒
`(1)/(3)(t) = 15`

⇒
`(1)/(3)(30) = 15`

⇒
`(30)/(3) =15`

⇒
`10=15`

We know that 10 ≠ 15 so the solution is incorrect.

According to the question :

Harry can first substitute (30) for t. He can the multiply 1/3 by (30) to get a product of (10). Since 15 (≠) equal to (10), Harry's solution is (not) correct.

Harry's solution is incorrect.