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The graph of which function has an axis of symmetry at x = 3?

f(x) = x2 + 3x + 1 On a coordinate plane, a parabola opens up. It goes through (negative 4, 5), has a vertex at (negative 1.75, 6.75), and goes through (1, 5).
f(x) = x2 – 3x – 3 On a coordinate plane, a parabola opens up. It goes through (negative 2, 7), has a vertex at (1.75, 5), and goes through (5, 7).
f(x) = x2 + 6x + 3 On a coordinate plane, a parabola opens up. It goes through (negative 6, 3), has a vertex at (negative 3, negative 6), and goes through (0, 3).
f(x) = x2 – 6x – 1 On a coordinate plane, a parabola opens up. It goes through (0, negative 1), has a vertex at (3, negative 10), and goes through (6, 0).

User Ola M
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2 Answers

3 votes

Answer:

D

Explanation:

User Alfred Fuller
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6.6k points
3 votes

Answer:

The function in the fourth option will have an axis of symmetry at x = 3.

Explanation:

We have to choose the function from options, the graph of which has an axis of symmetry at x = 3.

The function in the fourth option will have an axis of symmetry at x = 3.

It is f(x) = x2 – 6x – 1 On a coordinate plane, a parabola opens up. It goes through (0, negative 1), has a vertex at (3, negative 10), and goes through (6, 0). (Answer)

User Kefs
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