x ≤ 12
Solution:
Let us take the number be x.
A number : x
A number divided by three :
![$(x)/(3)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ymtze4yb7q0hhm5r9anuuk22v9ffpggijv.png)
A number divided by three less two :
![$(x)/(3)-2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/2m6k4nbhj9u2wusmp0ws4akxea6truugch.png)
A number divided by three less two is at most two :
![$(x)/(3)-2\leq 2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/t3n5gs28d2hf6b6vnp749l1wj0xfhoson4.png)
Now, simplify the inequality,
![$\Rightarrow(x)/(3)-2\leq 2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/14clgimrjejxpse1ppz0e88xfqtw9rf439.png)
Add 2 on both sides of the inequality,
![$\Rightarrow(x)/(3)-2+2\leq 2+2](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ykta8rpe37tmyaimalv2jak25n8uja4esx.png)
![$\Rightarrow(x)/(3)\leq 4](https://img.qammunity.org/2021/formulas/mathematics/middle-school/7qu1ltkwnfr1umyzxe40rdfm1kxxusgk11.png)
Multiply by 3 on both sides of the equation,
![$\Rightarrow(x)/(3)*3\leq 4*3](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ctrtt52uskgr3bb8f59jnmj261jt23tblx.png)
![$\Rightarrow x\leq 12](https://img.qammunity.org/2021/formulas/mathematics/middle-school/qcbxj2n8je30wd8k96gmhwbiu7ukdwig14.png)
Hence x ≤ 12.